Question

Two identical gardens are to be weeded, each by a two-person team. Team A includes one gardener who could weed the garden in 2 h and another who could weed the garden in 4 h. Team B includes two gardeners, either of whom could weed the garden in 3 h. Which team will finish first? Explain.

Answer 1

Given :-

• Team A includes one gardener who could weed the garden in 2 h and another who could weed the garden in 4 h.
• Team B includes two gardeners, either of whom could weed the garden in 3 h.

To Find :-

• Which team will finish first ?

Solution :-

Team A :-

→ one garden alone can weed the garden in = 2h.

→ his per hour Efficiency = (1/2) .

And, Similarly,

→ Efficiency of Second Gardener = (1/4) .

So,

→ Efficiency of Both Gardeners = (1/4) + (1/2) = (1+2)/4 = (3/4) .

So, They will Complete whole work in (4/3) hours.

______________________

Team B :-

→ Each gardener Took Time = 3 hours.

→ Efficiency of Each gardener = (1/3) .

→ Efficiency of Both gardener = 2 * (1/3) = (2/3).

So, They will Complete whole work in (3/2) hours.

______________________

Now, we can See That, Team A is Taking Less Time in Complete the whole work .

As , (3/2) > (4/3) .

Hence, we can say That, Team A will Finish first.

Answer 2

Question :

Two identical gardens are to be weeded, each by a two-person team. Team A includes one gardener who could weed the garden in 2 h and another who could weed the garden in 4 h. Team B includes two gardeners, either of whom could weed the garden in 3 h. Which team will finish first? Explain.

Solution :

Time To Weed Garden 1 :

$\dfrac{1}{ \dfrac{1}{2} + \dfrac{1}{4} } = \dfrac{4}{3} hr \: = 240 \: mins.$

Time to weed garden 2 :

$\dfrac{1}{ \dfrac{1}{3} + \dfrac{1}{43} } = \dfrac{3}{2} hr \: =90 \: mins.$

Hence Team A finishes first...