Math, asked by JOURI, 10 months ago

Two identical gardens are to be weeded, each by a two-person team. Team A includes one gardener who could weed the garden in 2 h and another who could weed the garden in 4 h. Team B includes two gardeners, either of whom could weed the garden in 3 h. Which team will finish first? Explain

Answers

Answered by RvChaudharY50
19

Given :-

  • Team A includes one gardener who could weed the garden in 2 h and another who could weed the garden in 4 h.
  • Team B includes two gardeners, either of whom could weed the garden in 3 h.

To Find :-

  • Which team will finish first ?

Solution :-

Team A :-

→ one garden alone can weed the garden in = 2h.

→ his per hour Efficiency = (1/2) .

And, Similarly,

→ Efficiency of Second Gardener = (1/4) .

So,

Efficiency of Both Gardeners = (1/4) + (1/2) = (1+2)/4 = (3/4) .

So, They will Complete whole work in (4/3) hours.

______________________

Team B :-

Each gardener Took Time = 3 hours.

→ Efficiency of Each gardener = (1/3) .

→ Efficiency of Both gardener = 2 * (1/3) = (2/3).

So, They will Complete whole work in (3/2) hours.

______________________

Now, we can See That, Team A is Taking Less Time in Complete the whole work .

As , (3/2) > (4/3) .

Hence, we can say That, Team A will Finish first.

Answered by VishnuPriya2801
16

Answer:-

Given:

In Team - A

Time taken by the first person to weed the garden = 2h

Part of the garden weeded by the person in a hour = 1/2

Time taken by the second person to weed the garden = 4 h

Part of the garden weeded by him = 1/4

Time taken by both to weed = 1/2 + 1/4

=> (2 + 1)/4

=> 3/4 = 4/3 hours.

In Team - B

Time taken by both the gardeners = 1/3 + 1/3

=> (1 + 1)/3

= 2/3 = 3/2 hours.

If we compare both the situations, Team - A took less time to complete

Hence, Team - A will finish the work first.

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