Two identical gardens are to be weeded, each by a two-person team. Team A includes one gardener who could weed the garden in 2 h and another who could weed the garden in 4 h. Team B includes two gardeners, either of whom could weed the garden in 3 h. Which team will finish first? Explain
Answers
Given :-
- Team A includes one gardener who could weed the garden in 2 h and another who could weed the garden in 4 h.
- Team B includes two gardeners, either of whom could weed the garden in 3 h.
To Find :-
- Which team will finish first ?
Solution :-
Team A :-
→ one garden alone can weed the garden in = 2h.
→ his per hour Efficiency = (1/2) .
And, Similarly,
→ Efficiency of Second Gardener = (1/4) .
So,
→ Efficiency of Both Gardeners = (1/4) + (1/2) = (1+2)/4 = (3/4) .
So, They will Complete whole work in (4/3) hours.
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Team B :-
→ Each gardener Took Time = 3 hours.
→ Efficiency of Each gardener = (1/3) .
→ Efficiency of Both gardener = 2 * (1/3) = (2/3).
So, They will Complete whole work in (3/2) hours.
______________________
Now, we can See That, Team A is Taking Less Time in Complete the whole work .
As , (3/2) > (4/3) .
Hence, we can say That, Team A will Finish first.
Answer:-
Given:
In Team - A
Time taken by the first person to weed the garden = 2h
Part of the garden weeded by the person in a hour = 1/2
Time taken by the second person to weed the garden = 4 h
Part of the garden weeded by him = 1/4
Time taken by both to weed = 1/2 + 1/4
=> (2 + 1)/4
=> 3/4 = 4/3 hours.
In Team - B
Time taken by both the gardeners = 1/3 + 1/3
=> (1 + 1)/3
= 2/3 = 3/2 hours.
If we compare both the situations, Team - A took less time to complete
Hence, Team - A will finish the work first.