Two identical glass (μg
= 3/2) equi convex lenses of focal
length f are kept in contact. The space between the two
lenses is filled with water (μw
= 4/3). The focal length of the
combination is -
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Answer:
Water in between the lens can be considered to be a concave lens of refractive index of water as shown in the figure. This suggests that the radius of curvature of all the lenses is same.
Consider the convex lens-
f
1
=
R
(μ
g
−1)2
=
R
(
2
3
−1)2
hence R=f
For the concave lens,
Power=
f
1
1
=(μ
water
−1)(
R
−2
)=
3f
−2
Power of the lenses get added,
f
combination
1
=
f
1
+
3f
−2
+
f
1
Hence f
combination
=
4
3f
solution
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