Two identical heaters rated 220v, 1000 watt are placedin series with each other across 220 volt line .Their combined power is
Answers
Given : Two identical heaters rated 220v , 1000 W are placed in series with each other across 220 volts line.
To find : The power of their combination.
solution : resistance of each heater, R = V²/P
= (220)²/1000 = 48400/1000 = 48.4 Ω
as both heaters are connected in series combination.
equivalent resistance of combination, Req = R + R = 2R = 2 × 48.4 = 96.8 Ω
now combined power = V²/Req
= (220)²/96.8
= 48400/96.8
= 500 W
Therefore combined power is 500 Watt.
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Answer:
Let resistance of each heater be
R
Ω
Given that the power of each heater is 1000W when connecred across 240V.
So
1000
=
240
2
R
⇒
R
=
240
2
1000
Ω
When two heaters are connected in serises total resistance
2
R
=
240
2
500
Ω
Then total power consumed
=
240
2
240
2
500
=
500
W
Explanation: