Two identical lamps A and B using different types of kerosene can completely utilize the same volume of oil in 12 hours and 8 hours respectively, due to the quality of oil used. If both of them start burning at the same time at their respective constant speed, then after what time does the ratio of the height of kerosene oil left will become 4:3.
Answers
Given : Two identical lamps A and B using different types of kerosene can completely utilize the same volume of oil in 12 hours and 8 hours respectively
both of them start burning at the same time at their respective constant speed
To Find : after what time does the ratio of the height of kerosene oil left will become 4:3.
Solution:
Assuming Shape of oil tank as cylinder or cuboid
Where Volume is directly proportional to height
Let say Volume = 24X
lamps A utilize in 12 hrs = 24X
=> lamps A utilize in 12 hrs = 24X/12 = 2X
=> lamps A utilize in T hrs = 24X/12 = 2XT
lamps B utilize in 8 hrs = 24X
=> lamps B utilize in 8 hrs = 24X/8 = 3X
=> lamps B utilize in T hrs = 24X/12 = 3XT
Volume remaining in A = 24X - 2XT
Volume remaining in B = 24X - 3XT
(24X - 2XT)/(24X - 3XT) = 4/3
=> 72X - 6XT = 96X - 12XT
=> 6XT = 24X
=> T = 4
After 4 hrs the ratio of the height of kerosene oil left will become 4:3.
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Answer:
4hr
Step-by-step explanation:
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