Two identical masses of 5 kg each fall on a wheel from a height of 10m will disturb the mass of 2 kg water the rise in the temperature of the water will be
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Weight of mass = 5kg (Given)
Height = 10m (Given)
Mass of Water = 2kg(Given)
To calculate the formula used will be -
W = J Q
Therefore,
2m * g* h = J * m' * Cp * Delta T
= 2 *5*10*10 = 4.2 *(2* 1000* delta T)
= Delta T = 0.12°c
Thus, if the mass of water is disturbed, the rise in the temperature of water will be 0.12°c
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