Two identical metal balls at temperature 200 and 400 kept in air
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Explanation:
If the temperature of the surrounding is considered then
net loss of energy of a body by radiation
Q=Aϵσ(T4−T04)t⇒Q∝(T4−T04)⇒Q1Q2=T14−T04T24−T04Q=Aϵσ(T4−T04)t⇒Q∝(T4−T04)⇒Q1Q2=T14−T04T24−T04
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