Two identical metal spheres A and B carry charges q and 2q respectively. When the two spheres are at distance r from each other, the electrostatic force acting between them is F. Another identical but chargeless sphere is first brought in contact with A, then it is touched to sphere B and then separated from it. Now the force acting between A and C at same distance is ...............
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Pic does not has correct answer
Charge on C is 5q/4 instead of q(i have done in attachment)
So multiply -
F/4×5/4=5F/16
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It goes to A and acquires q/2 then to B and takes half of total charge (q/2+2q=5q/2)
So takes 5q/4
Pic does not has correct answer
Charge on C is 5q/4 instead of q(i have done in attachment)
So multiply -
F/4×5/4=5F/16
.
.
.
.
.
It goes to A and acquires q/2 then to B and takes half of total charge (q/2+2q=5q/2)
So takes 5q/4
Attachments:
Heta11:
No Answer is 5F/16
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