Two identical metal spheres carry charges of +q and -2q reap when the spheres are separated by a large distance r the force between them I'd F now the spheres are allowed to touch and then moved back to the same separation find the new force of repulsion between them
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Answer:
(kq^2)/4r^2
Explanation:
avg. of both spheres ={q+(-2q)}/2=-q
and proceedings same as basic questions by applying kq1q2/ r2
nasreenmemon2:
Thank uh
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