two identical metallic balls A and B have charges +40and_10micro colomb the distance between them is2.0m what is the magnitude and type of force acting between them they are touched to each other and again separated by a distance of2.0m from each other calculate the new force between them what will be the force if one ball is connected to earth?????
Answers
Answered by
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The magnitude and type of the force will be 0.5 N and repulsive.
Explanation :
When both balls are touched to each other, then charge between them will be distributed equally,
New charge
Q = (+40 - 10)/2 = 15 μC = 15 x 10⁻⁶ C
distance r = 2 m
Hence force between them,
F = 1/4πε₀ x QQ/r²
= 9 x 10⁹ x 15 x 10⁻⁶ x 15 x 10⁻⁶/4
= 506 x 10⁻³ N
= 0.5 N
So, the magnitude of the force will be 0.5 N
The nature of the force will be repulsive as these balls have same charges.
When one of the ball will be touched to the ground, then it completely becomes neutral i.e. 0 charge, hence the new force between them will be zero.
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Answer:
it is so simple when one ball will touched the earth then it becomes neutral so charge become zero then forcewill be zero
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