Question

Two identical non- relativistic particles A and B move at right angles to each other, having de-broglie wavelengths 1 and 2 respectively. The de-broglie wavelength of each particle in their centre of mass frame of reference is

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Vcm = m1v1 + m2v2 / m1+m2

      = v1 + v2 / 2

All are in vector form

λ = h/mvc

V1,cm(with resppect to cm ) = V1 - v2 /2

V1cm = V2cm

λcm = 2λ1λ2/ √(λ1² +λ2² )