Question

Two identical objects A and B of mass M moving along the same vertical line in opposite directions at the same time. Object a is dropped from rest from a height h above the ground and object b is projected vertically upward from the ground with speed u=root 2g11
at what height above the ground do they collide

Answer 1

Answer:

Height from the ground where they collide is given as

$y = \frac{3h}{4}$

Explanation:

As we know that the two objects are projected along same line

So during their motion the relative acceleration of two objects will be zero

So we have

$d = v_{rel} t$

so here we have

$v_{rel} = \sqrt{2gh}$

now we have to find the time when they collide

so we have

$t = \frac{d}{v_{rel}}$

$t = \frac{h}{\sqrt{2gh}}$

$t =\sqrt{ \frac{h}{2g}}$

so the height where they collide is given as

$y = h - \frac{1}{2}gt^2$

$y = h - \frac{1}{2}g(\frac{h}{2g})$

$y = h - \frac{h}{4}$

$y = \frac{3h}{4}$

#Learn

Topic : relative motion

https://brainly.in/question/1468249

Answer 2

Answer:

answer is 3/4 of h

Explanation:

3/4 of h