Question

Two identical objects, separated by a distance d, with charges equal in magnitude but of opposite signs exert a force of attraction of - 2.5 N on each other. What force do these objects exert on each other if the distance between them becomes 2d?​

Answer 1

$\huge\underline\mathfrak{\pink{ Solution}}$

Let the two charges be q and -q. The magnitude of the force that q and -q, separated by a distance d, exert on each other is given by Coulomb's law:

$\red{F = k (q) (- q) / d2 = - k q2 / d2 = - 2.5 N}$

The magnitude of the force F2 that q and -q, separated by a distance 2 d, exert on each other is given by Coulomb's law:

$\red{F2 = k (q) (- q) / (2 d)2 = - k q2 / 4 d2 = F / 4 = - 2.5 / 4 = - 0.625 N}$

Answer 2

Explanation:

Hope it will help you

Follow me please