Question

two identical parallel plate capacitors are connected in parallel and joined to a 6v battery. the battery is then disconnected and the two capacitors are joined in series. the potential difference is
1)3v 2) 6v 3) 9v 4) 12v​

Answer 1

Answer:

So the voltage difference of the combination of two capacitors is 12 Volts

Explanation:

When two identical capacitors are connected in parallel across the battery then the charge on each capacitor is given as

$Q = CV$

so we have

$Q = 6 C$

now when two capacitors are disconnected from the battery then the charge will remain conserved on the plates of capacitor

so the new capacitance of two capacitors in series is given as

$\frac{1}{C_{net}} = \frac{1}{C_1} + \frac{1}{C_2}$

$C_{net} = \frac{C}{2}$

now the potential difference of the system of two capacitors is

$V = \frac{q}{C_{net}}$

$V = \frac{6C}{\frac{C}{2}}$

$V = 12 volts$

#Learn

Topic : Combination of capacitor

https://brainly.in/question/9933150