Question

Two identical particles are attached by an inextensible and mass less string which passes over a smooth fixed cylinder of radius R as shown in figure Initially particles are kept at rest. If the system is released
tangential acceleration of particle in contact with cylinder is
2M
OM​

Answer 1

Answer:

In the given figure two identical particles each of mass m are tied together with an inextensible string. This is pulled at its centre with a constant force F. If the whole system lies on a smooth horizontal plane, then the acceleration of each particle towards each other is:

Explanation:

Let the tension developed in both the strings be T,as their masses are assumed to be equal.Now balancing components along x axis we get, 2Tcos30=F,which gives T=

3

F

.

Now,both the masses have acceleration a=

2

3

m

F

,towards each other i.e. in opposite direction.So,the acceleration with which both masses approach each other is =

2

3

m

F

+

2

3

m

F

.So, option b is correct.