Two identical point charge Q.Q are kept at a distance T apart A third point-charge q is placed on the
Ime joining the above two charges such that all the three charges are in equilibrium What is the
magnitude, sign and position of the third charge!
Ans. A negative charge of magmtude 74 should be placed mid-way between the charges +and +0.
In this condition the net force on each charge will be zero. The equilibrium is unstable
lications of Coulomb foree:
Answers
Answer:Let the system be like the figure drawn above.
Now for the system to be in equilibrium the net force on each of the three charges must be zero.
Due to symmetry of the system the net force on the “q” charge will be zero automatically.
So now, we focus on charge “Q” on right and left sides.
Each “Q” is experiencing two forces. One due to the other “Q” and one due to “q”.
Hence the net force on each of them is then
F = F( due to Q) + F ( due to q)
= (k.Q.Q)/r^2 (towards left) + (kQq)/(r/2)^2(towards right)
Since, F=0
Hence Q=4q { in magnitude}
But since force between Q...(more)
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