Question

Two identical pumps fill a water reservoir in 10 hours. How many additional pumps should be turned on if the reservoir must be filled in 4 hours?

Answer 1

Answer:

3 additional pumps

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

$3$ additional pumps should be turned on if the reservoir must be filled in 4 hours.

Given:

Two identical pumps fill a water reservoir in 10 hours.

To Find:

We need to find how many additional pumps should be turned on if the reservoir must be filled in 4 hours.

Solution:

We need to find time taken for each pump to fill a water in reservoir.

$T$ - Total Time taken = 4

$n(p)$ - number of pumps = 2

$t(1)$ - Time taken for one pump

Time taken for one pump,

$t(1) = T * n(p)$

$t(1) =10 * 2$

$t(1) = 20$

Time taken for one pump to fill water is 20 hours.

Total hours to fill a reservoir = 4 hours

$n(x)$ - Total number of pump needed to fill in 4 hours.

$T$ - Total time = 4 hours

$n(x) = \frac{t(1)}{T}$

$n(x) = \frac{20}{4}$

$n(x) = \frac{5*4}{4}$

$n(x) = 5$

Total number of pump needed to fill in 4 hours $= 5$

We already have 2 identical pumps.

Additional pump needed = Total number of pumps needed - available pumps

Additional pump needed $= 5 - 2$

Additional pump needed $= 3$

Therefore, $3$ additional pumps should be turned on if the reservoir must be filled in 4 hours.

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