Question

Two identical resistances of 12 w each are connected to a battery of 3 V. Calculate the ratio of the power consumed by minimum and maximum resistance.​

Answer 1

Answer:

resistance watt se nai ohms se denote hota

and agar vo watt hai so that must be resistance

Answer 2

Explanation:

answer : 4 : 1

explanation : Two identical resistors of 12 ohm each are connected to a battery 3 volt.

minimum resistance is possible only when both resistors are connected in parallel combination.

so, Req = 12 × 12/(12 + 12) = 6 ohms.

Maximum resistance is possible only when both the resistors are connected in series combination.

so, Req = 12 + 12 = 24 ohms.

we know, power consumed by wire is given by, P = V²/R

hence, Power is inversely proportional to resistance.

so,$\frac{P_1}{P_2}=\frac{R_2}{R_1}$

here, R_2=24$\text{\O}mega,R_1=6\text{\O}$

or, $\frac{P_1}{P_2}=\frac{24}{6}=\frac{4}{1}$