Question

Two identical resistors
are first connected in series and then in parallel find the ratio of equilant resistance in two cases

Answer 1

Answer:

The Ration will be R1*R2:1

Explanation:

let the resistances be R1 and R2

so, when connected in series: equivalent resistance= R1+R2

And when connected in parallel: equivalent resistance= 1/R1+ 1/R2

                            = R1+R2/R1*R2

now The ration of the resistances= R1+R2/ R1+R2/R1*R2 I.e. series resistance/ parallel resistance

=> (R1+R2)R1*R2/ R1+R2

now R1+R2 will cancel each other

therefore, equivalent resistance = R1*R2