Two identical resistors are first connected in series and then in parallel.Find the ratio of equivalent resistances in two cases.
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Answered by
13
Let one of the resistor be R
Eqv. resistance of the resistor connected in series Rs = 2R
Eqv. resistance of the resistor connected in parallel
1/ Rp = 1/R + 1/R
=> Rp = ½R
1.) Ratio of eqv. resistance in both the case is
Rs/Rp = 2R/ (R/2)
= 4:1
Eqv. resistance of the resistor connected in series Rs = 2R
Eqv. resistance of the resistor connected in parallel
1/ Rp = 1/R + 1/R
=> Rp = ½R
1.) Ratio of eqv. resistance in both the case is
Rs/Rp = 2R/ (R/2)
= 4:1
rohit710:
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Answered by
5
let the resistances be R
In Series:
total resistance R1 = R+R
= 2R
therefore equivalent resistance of series = 2R
In Parallel:
toal resistance R2 = (R*R) / (R+R)
= R² / 2R
therefore equivalent resistance of parallel = R² / 2R
Ratio of their Equvalent Resistance =2R/ (R² / 2R)
= 4 R² /R²
= 4 : 1
In Series:
total resistance R1 = R+R
= 2R
therefore equivalent resistance of series = 2R
In Parallel:
toal resistance R2 = (R*R) / (R+R)
= R² / 2R
therefore equivalent resistance of parallel = R² / 2R
Ratio of their Equvalent Resistance =2R/ (R² / 2R)
= 4 R² /R²
= 4 : 1
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