two identical resistors are first connected in series and then in parallel to a source supply find the ratio of heat produced in 2 cases
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Hope it helps..........
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rockyrohan:
why in the second equation you divided I square by 4
square of I by two as equal current will pass through to the two resistance so we will divide the current into two equal parts
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When two resistors are connected.....then
Heat produced= I^2Rt..
Now in case of series combination..
Heat= I^2(2R)t
In Parallel Combination..
Heat produced= I^2(R/2)t
H(s) / H(r) =I^2(2r)t/ I^2(R/2)t
H(s)=4H(p)
Thus, Heat produced in a parallel combination is 4 times then that of series combination...
Heat produced= I^2Rt..
Now in case of series combination..
Heat= I^2(2R)t
In Parallel Combination..
Heat produced= I^2(R/2)t
H(s) / H(r) =I^2(2r)t/ I^2(R/2)t
H(s)=4H(p)
Thus, Heat produced in a parallel combination is 4 times then that of series combination...
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