Question

Two identical resistors, each of res
each of resistance 15 ohm are connected in
(i) series, and (ii) parallel, in turn to a Day
in turn to a battery of 6 V. Calculate the ratio
wer consumed in the combination of resisto

Answer 1

Answer:

sorry i dont know iam week in physics

Answer 2

The ratio  power consumed in the combination of resistor is $\dfrac{1}{4}\ .$

Case I :

When both are in series :

Therefore , total resistance , $R = 15 + 15 = 30\ \Omega$ .

Therefore , current flowing through,  

$I=\dfrac{V}{R}\\\\I=\dfrac{6}{30}\\\\I=0.2\ A$

Therefore , power ,

$P_s=V.I\\\\P_s=0.2\times 6\\\\P_s=1.2 \ W$

Case II :

When both are in parallel :

Therefore , total resistance ,

$\dfrac{1}{R} = \dfrac{1}{15} +\dfrac{1}{15}\\\\R=7.5\ \Omega$ .

Therefore , current flowing through,  

$I=\dfrac{V}{R}\\\\I=\dfrac{6}{7.5}\\\\I=0.8\ A$

Therefore , power ,

$P_p=V.I\\\\P_p=0.8\times 6\\\\P_p=4.8 \ W$

Therefore , their ratio is :

$\dfrac{P_s}{P_p}=\dfrac{1.2}{4.8}\\\\\dfrac{P_s}{P_p}=\dfrac{1}{4}$

Hence , this is the required solution .

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Resistance

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