Question

Two identical resistors each of resistance 10 ohm are connected in parallel . This combination is turn is connected to the third resister of 10ohm . The eqivalent resister of the combination is

Answer 1

Answer:

15 ohm

Explanation:

because first two resistances are in parallel

1/Rp=1/10+1/10

Rp=10/2=5 ohm

then 5 ohm resistors connected in turns means it is connected in series

Rs=10+5=15 ohm

Answer 2

The equivalent resister of the combination is 15 ohms.

Explanation:

Given that,

Two identical resistors each of resistance 10 ohm are connected in parallel. The equivalent resistance in parallel combination is given by :

$\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\\\\\dfrac{1}{R}=\dfrac{1}{10}+\dfrac{1}{10}\\\\R=5\ \Omega$

Now the equivalent resistance in turn is connected to the third resister of 10 ohms, it means now connected in series. Equivalent reisistance now given by :

R = 5 ohms + 10 ohms

R = 15 ohms

Hence, the equivalent resister of the combination is 15 ohms.

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