Two identical resistors each of resistance 10 ohm are connected in (a) series (b) parallel in turns to a battery of 6v. Calculate the ratio of power consumed in the combination of resistors in two case.
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in series
Req = 10+6=16ohm
in paralllel
Req = 60/16ohm
p = v^2R
p1/p2 = 36*60/36*16*16
p1/p2 = 60/16*16 = 15/64
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