Two identical resistors each of resistance 10 ohm are connected in series and parallel in line to a battery of 6volts . Calculate the ratio of power consumed in the combination of resistors in the two cases
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V=6v
R1=10 ohm
R2=10 ohm
Connected in seris power consumption
= v^2/r
=6×6/10+10
=36/20W. (1)
Connected in parallel
Total resistance
1/R=1/10+1/10
= 2/10
=1/5. =>R =5 (2)
Power con sumed
=v^2/r
=36/(5)
Ratio of power consumption
=(36/20)/(36/5)
=36/20×5/36
=1/4
1:4
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