Question

Two identical resistors each of resistance 10 ohm are connected in series parallel to a 6 volt battery calculate the ratio of power consumed in the combination of resistors and two cases

Answer 1

The resistance in series combination is 20Ω and in parallel combination is 5Ω. The ratio of power is 0.25 W

Explanation:

• 1) Resistance in series combination:

10 + 10 = 20Ω

Now find the current

I=V/R  = 6/20 = 0.3 A

Now power

P1=V(I)  =6 × 0.3 = 1.8 W

• 2) Resistance in parallel combination:

1/R = 1/R + 1/R

      = 1/10+1/10

   R = 5Ω

• Now current in the battery.

I = V/R = 6/5 = 1.2 A

• Power of battery:

P2 = V × I  = 6×1.2 =7.2 W

• Ratio of power consumed:

P1/P2 =  1.8/7.2

         = 0.25 W

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