two identical resistors each of resistance 10ohm are connected in.a)series (b) parallel calculate the equivalent in each case
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Answer:
a. series: 20 ohm
b. parallel: 5 ohm
Answered by
1
Given :
- R ₁ = R ₂ = R = 10Ω
Solution :
(a)
Equivalent resistance for n number resistors connected in series is given by the formula ,
- Rₛ = R ₁ + R ₂... + Rₙ
Hence ,
⇒ Rₛ = R ₁ + R ₂
⇒ Rₛ = 2R
⇒ Rₛ = 20 Ω
The equivalent resistance of the combination is 20 Ω.
(b)
Equivalent resistance for n number resistors connected in series is given by the formula ,
- 1 / Rₚ = 1 / R ₁ + 1 / R ₂... + 1 / Rₙ
Hence ,
⇒ 1 / Rₚ = 1 / R ₁ + 1 / R ₂
⇒ 1 / Rₚ = 1 / R + 1 / R
⇒ 1 / Rₚ = 2 / R
⇒ Rₚ = R / 2
⇒ Rₚ = 10 / 2
⇒ Rₚ = 5 Ω
The equivalent resistance of the combination is 5 Ω.
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