Two identical resistors, each of resistance 10ohm are connected in series and in parallel to volt cell.Calculate the ratio of powers in each case
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Hey.
We have :
Two identical resistors each 10 ohm.
Let V be the potential difference of the cell.
Equivalent resistance :
In series : Rs = r1 + r2
so, Rs = 10 + 10 = 20 ohm
In parallel :
1/Rp = 1/r1 + 1/r2
=> Rp = (r1.r2 / r1+r2 )
so, Rp = (10×10 / 10+10) = 100/20 = 5 ohm
Now, As Power = V^2/ R
So, Ps = V^2/20
& Pp = V^2/5
Hence , Ratio, Ps/Pp = (V^2/20)/(V^2/5)
= 5/20 = 1/4
Hence , Ps : Pp = 1 : 4
Thanks.
We have :
Two identical resistors each 10 ohm.
Let V be the potential difference of the cell.
Equivalent resistance :
In series : Rs = r1 + r2
so, Rs = 10 + 10 = 20 ohm
In parallel :
1/Rp = 1/r1 + 1/r2
=> Rp = (r1.r2 / r1+r2 )
so, Rp = (10×10 / 10+10) = 100/20 = 5 ohm
Now, As Power = V^2/ R
So, Ps = V^2/20
& Pp = V^2/5
Hence , Ratio, Ps/Pp = (V^2/20)/(V^2/5)
= 5/20 = 1/4
Hence , Ps : Pp = 1 : 4
Thanks.
Elwin123:
Thanks
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