Question

Two identical resistors each of resistance 10ohm are connected in series and parallel in turn to a battery of 10V. Calculate the ratio of power consumed in combination of resistos in the two cases

Answer 1

in series-

Rs= 10+10ohm

= 20ohm

P1=V2/R

= 10×10/10

=10w

In parllel-

Rq= 10×10/10+10

=100/20

=5ohm

P2=10×10/5

=20w

ratio = P1/P2

=10/20

=1:2