Two identical resistors each of resistance 12 ohm are connected in series and parallel in turn to a battery of 6 volt. Calculate the power consumed by the combination in each case
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Answer:Series Power:1.5 W
Parallel Power:9W
Explanation:
Total Resistance for series combination: 12 ohm +12 ohm = 24ohm
Power = V²/R
=>P = 36V²/24ohm = 1.5 W
Total resistance for parallel combination:
1/12ohm +1/12 ohm = 1/R
=> R = 6ohm
Therefore, P = V²/R
=> P = 36V²/6 = 9 W
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