Two identical resistors, each of resistance 2Ω, are consumed in turn : (i) in series and (ii) in parallel to a battery of 12 V. Calculate the ratio of powers consumed in two cases.
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Answered by
3
Answer:
1 : 4
Explanation:
Total resistance in series, R₁ = 2Ω + 2Ω = 4Ω
Power consumed in series connection, P₁ = V²/ R₁ = 12²/ 4 = 36 W
Total resistance in parallel, R₂ = (2 × 2)/ (2 + 2)Ω = 1Ω
Power consumed in parallel connection, P₂ = V² / R₂ = 12²/ 1 = 144 W
Thus, P₁ / P₂ = 36 W / 144 W = 1/4 or P₁ : P₂ = 1 : 4
Answered by
0
Answer:
1 : 4 is the answer
Explanation:
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