Two identical resistors each of resistance 20 ohm are connected a)in parallel b) in series in turn to a battery of 10 V. calculate the ratio of power consumed in the combination of resistors in the two cases
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series
nR = 2×20 =40ohm
parallel
R/2 = 20/2 = 10ohm
Ratio = 40/10 = 4:1
nR = 2×20 =40ohm
parallel
R/2 = 20/2 = 10ohm
Ratio = 40/10 = 4:1
raminder1:
hi
thanks dude
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