Question

Two identical resistors each of resistance 20 ohm are connected: (i) In series. (ii) In parallel, in turn to a battery of 6V. Calculate the ratio of power connected in the combination of resistors​

Answer 1

Answer:

45volt

6:8

Explanation:

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Answer 2

Taking 2 cases here-->

Case 1- Resistors are connected in series (Pic 1)

We know that when resistors are connected in series combination then the total resistance R will be

R=R1+R2

R=10+10

R=20 ohms

Given that, V=6 volts

So, current I will be

I=V/R (ohm's law)

I=6/20 or 3/10 ampere

P=$I^{2} *r$

P=(3/10)^2*20

P=9/100*20

P=9/5 watt

Case 2- The resistors are connected in parallel combination (Pic 2)

So, 1/R=1/R1+1/R2

1/R=1/10+1/10

1/R=1/5

R=5 ohms

Given, V=6 volts

I=V/R

I=6/5 ampere

P=$I^{2} *r$

P=(6/5)^2*5

P=36/25*5

P=36/5 watt

Now, we are asked the ratio of the powers in the question

So, Ratio=Power in series/Power in parallel

Ratio= 9/5/36/5

Ratio= 1/4

Ratio=1:4 (Answer)

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