Question

Two identical resistors, each of resistance 50Ὡ are connected (i) in series (ii) in parallel, in turn, to a battery of 10V.Draw the circuit and find the value of current in the combination of resistors in the two cases.

Answer 1

Answer:

ANSWER

When the two resistors are in series, total resistance = R

s

=10+10=20Ω

I

s

=

R

V

=

20

6

=0.3A

When the two resistors are connected in parallel, total resistance :

R

p

1

=

10

1

+

10

1

⇒R

p

=5Ω

I

p

=

5

6

=1.2A

Power = V I

Thus, the ratio of power consumed in series and parallel combination is;

P

p

P

s

=

1.2

0.3

=0.25. Please mark the answer as the branliest

Answer 2

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