Question

Two identical resistors of 12ohm each are connected to a battery of 3volts. Calculate the ratio of the power consumed by the resulting combinations with minimum resistance and maximum resistance

Answer 1

Hey mate ☺

Let a Conductor A and Conductor B of 12 ohm each.

In series combination,

R = R₁ + R₂

R = ( 12 + 12 ) ohm

R = 24 Ω

I = V/R

I = 3/24 = 1/8 A

P = VI

Power = 3 × 1/8 W or 3/8 W

In parallel combination,

1/R = 1/R₁ + 1/R₂

1/R = 1/12 1/12

1/R = 2/12 ohm

1/R = 1/6

R = 6 Ω

I = V/R

I = 3/6 or 1/2 A

Power = 3 × 1/2 W or 3/2 W

Also, we have to find minimum to maximum ratio

Here, parallel resistance is minimum while series one is maximum.

Therefore, Ratio = ( 3/2 ) ÷ ( 3/8 )

= 3/2 × 8/3

= 4 / 1

Ratio = 4 : 1

Hope it helps you ☺✌✌

Answer 2

Answer:

Step-by-step explanation: