Question

two identical resistors of 7 ohm each are connected to a battery of 6 volt calculate the ratio of power consumed by resulting combination with minimum resistance and maximum resistance

Answer 1

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Answer 2

With minimum resistance the resistors will be connected in parallel.

For minimum resistance:

1/Rt = 1/R1 + 1/R2

Rt = effective resistance

R1 = R2 = 7 ohms

Doing the substitution we have :

1/Rt = 1/7 + 1/7

= 2/7

Rt = 7/2 = 3.5 ohms

At maximum resistance the resistors are connected in series:

Rt = R1 + R2

= 7 + 7 = 14 ohms.

The formula for power is given as :

Power = V²/R

Power at Minimum resistance is given by:

P1 = 6²/3.5 = 10.29 watts

Power at maximum resistance :

P2 = 6²/14

= 36/14 = 2.57 watts

P1 : P2 is given by :

36/3.5 × 14/36

= 4/1

= 4 : 1