Two identical resistors of resistance 100 ± 5 ohm are connected parallel. Calculate the
equivalent resistance of the combination.
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Answer:
Explanation:
Given, R=(100±5)Ω
In parallel combination
1R.=1R+1R=2R
or △R.(R.)2=2△RR2
△R.=(R.)2×2×△R(R)2
⇒△R.=(R2)2×2△R(R)2
⇒△R.=(1002)2×2×5(100)2
⇒△R.=2.5
R.=1002±2.5
⇒R.=(50±2.5) ohm.
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