two identical resistors of resistance 2 ohms are connected in series and parallel to a 12 V battery calculate the power in both the cases
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total resistance in series = R1 + R2
= 2 + 2 = 4 ohm.
total resistance in parallel combination = 1/R1+1/R2 = 1/2+1/2 = 1 ohm.
V = 12V
Power in series = V2/R = 12 . 12/4 = 36W
power in parallel combination = V2/R
= 12 . 12/1
= 144W. is the answer.
= 2 + 2 = 4 ohm.
total resistance in parallel combination = 1/R1+1/R2 = 1/2+1/2 = 1 ohm.
V = 12V
Power in series = V2/R = 12 . 12/4 = 36W
power in parallel combination = V2/R
= 12 . 12/1
= 144W. is the answer.
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