Two identical resistors of resistance Rare connected in series with a battery of potential difference V for time t. The resistors are then connected in parallel with the same battery for the same time t. Compare the heat produced in the two cases.
Answers
Given that, two identical resistors of resistance R are connected in series and then in parallel with a battery of potential difference V for time t.
When connected in series combination:
Rs = R + R
Rs = 2R
When connected in parallel combination:
1/Rp = 1/R + 1/R
1/Rp = 2/R
Rp = R/2
Ratio of series and parallel:
Rs/Rp = 2R/(R/2)
Rs/Rp = 4/1
Heat produced when in series combination:
H = I²Rt
(I = V/R and R = 2R)
Hs = (V² × 2Rt)/(2R)²
Hs = V²t/2R
Heat produced when in parallel combination:
H = I²Rt
Hp = V²/(R/2)² × Rt/2
Hp = 4V²/R² × Rt/2
Hp = 2V²t/R
(Hs for heat in series and Hp for heat in parallel)
Ratio of heat produced in series and parallel:
Hs/Hp = (V²t/2R)/(2V²t/R) =1/4
Hs = 1/4 Hp
Therefore, the heat produced in series is 1/4 times of the heat produced in parallel.
Explanation:
hey here is your ans!! hope it's correct thank you do much for ur support