Question

Two identical spheres having charges 8 micro C and 2 micro C are placed in air with their centres 3
m apart. The spheres are now connected by a metallic wire. Calculate the electrostatic force
between them​

Answer 1

Explanation:

After conection charges will redistribute.

So, Charge on each sphere = 10/2 = 5 micro C

Therefore, Force =

$k \frac{q \times q}{ {r}^{2} } = 9 \times {10}^{9} \times \frac{5 \times 5 { \times 10}^{ - 12} }{ {3}^{2} } = \: \: \: \: \: \: 25 \times {10}^{ - 3}$

Hope you got it.