Question

Two identical spheres, having charges of
opposite sign attract each other with a force of 0.108 N when
separated by 0.5 m. The spheres are connected by a conduc-
ting wire, which then removed, and thereafter they repel each
other with a force of 0.036 N. What were the initial charges
on the spheres ?​

Answer 1

Answer:

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Explanation:

Let initial charge be Q1 and Q2.

Initial force =F=  

r  

2

 

K×Q1×Q2

​  

=−0.108

F=  

0.25

9×10  

9

×Q1×Q2

​  

=−0.108

Q1.Q2=−3×10  

−12

 

Now on connecting them, since they are identical so they will have equal charges.

Final charge =  

2

Q1+Q2

​  

 

Final force =F=  

4×0.25

9×10  

9

×(Q1+Q2)  

2

 

​  

=0.036

Q1+Q2=±2×10  

−6

 

Q2=±1.0×10  

−6

C,Q1=∓3.0×10  

−6

C