Question

Two identical spherical charged metallic spheres (same charge) are hung by strings make 60° with eqch other in vaccum. When the whole arrangment is kept in a liquid of density 0.5g/cc , the angle remains same. Calculate the electric constant of fluid. ​

Answer 1

Answer:

From fig,

tanθ=qE/mg

tan15o=d2mgkq2

tan15o=1.6Vgd2kq2 .....[V is the volume]...........(1)

When system is suspended in liquid,

tan15o=K(mg−ρVg)d2kq2 

tan15o=K(1.6−0.8)Vgd2kq2 ......(2)

 from (1) and (2) we get,

K(1.6−0.8)Vgd2kq2=1.6Vgd2kq2 

∴K=2=Dielectric constant of liquid.

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Answer 2

QUESTION:-

Two identical spherical charged metallic spheres (same charge) are hung by strings make 60° with eqch other in vaccum. When the whole arrangment is kept in a liquid of density 0.5g/cc , the angle remains same. Calculate the electric constant of fluid.

ANSWER:-

tanθ=qE/mg

tan15o=d2mgkq2

tan15o=1.6Vgd2kq2 .....[V is the volume]...........(1)

When system is suspended in liquid,

tan15o=K(mg−ρVg)d2kq2 

tan15o=K(1.6−0.8)Vgd2kq2 ......(2)

 from (1) and (2) we get,

K(1.6−0.8)Vgd2kq2=1.6Vgd2kq2 

∴K=2=Dielectric constant of liquid.

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