Two identical springs of constant k are
connected, first in series and then in
parallel. A metal block of mass m is
suspended from their combination. The
ratio of their frequencies of vertical
oscillations will be in a ratio
A. 1:4
B. 1:2
C. 2:1
D. 4:1
Answers
Answer:
Radius of circle is 49.9 cm (approx).
Area of circle is 7825.74 cm² (approx).
Explanation:
Given :-
Circumference of circle is 314 cm.
To find :-
Radius of circle.
Area of circle.
Solution :-
Circumference of circle = 2πr
Where,
r is radius of circle.
π is 22/7 or 3.14 .
Put the values :
\rightarrow → 314 = 2πr
\rightarrow → 314 = 2 × 22/7 × r
\rightarrow → 314 = 44/7 × r
\rightarrow → 314 × 7 = 44 × r
\rightarrow → 2198 = 44 × r
\rightarrow → 2198/44 = r
\rightarrow → r = 49.9
Thus,
Radius of circle is 49.9 cm (approx).
Now,
We know,
Area of circle = πr²
Put r in formula :
\rightarrow → 22/7 × (49.9)²
\rightarrow → 22/7 × 2490.01
\rightarrow → 54780.22/7
\rightarrow → 7825.74
Therefore,
Area of circle is 7825.74 cm² (approx).
Explanation:
B. 1 : 2
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