Question

Two identical square mods of metal are welded end to end
as shown in figure (a) 20 calories of heat lows through it
in 4 minutes. If the rods are welded as shown in the same
amount of heat will flow through the rods in-
0°C
0°C
- 100°C
(a)
(a) Iminutes
(c) 4 minutes
(b) 2 minutes
(d) 16 minutes​

Answer 1

Answer:

The rate at which the heat is developed is given by

d t

d Q

=

L

KAδT

d t

d Q

=

2x

KAδ(T

1

−T

2

)

=5

Now , we have

d t

d Q

=

x

2KAδT

Therefore by solving above we have , t=2 minutes

So (b) 2 minutes is your answer !!

Explanation:

Hi !!

Hope it helps you !!

Answer 2

The rate at which the heat is developed is given by

dt

dQ

=

L

KAδT

dt

dQ

=

2x

KAδ(T

1

−T

2

)

=5

Now , we have

dt

dQ

=

x

2KAδT

Therefore by solving above we have , t=2 minutes

I hope it's help you