Question

Two identical tanks contain water and a liquid of

density 0.8 g cm−3. Pressure exerted by the liquid is

equal to the pressure due to water column of 50 cm.

Find the height of the liquid column in the tank?​

Answer 1

Answer:

50cm=0.5m    0.8g cm⁻³=800kg/m³  density of water=1000 kg/m³

pressure exerted by 50cm water=ρgh=1000x10m/s²x0.5m=5000Pa

 

   pressure exerted by liquid=pressure due to water coulmn of 0.5m

-->     ρ g h                              =  5000

    >  800x10xh                =  5000

    >    height of liquid column =0.625 m

                                                         

Answer 2

Explanation:

By using principle of hare's apparatus,

R.D = h1÷h2

R.D = Density of the liquid / Density of the water of same volume at 4°C

====> 0.8/1 = 0.8

H1 = 50 cm

0.8 = 50/H2

H2 = 62.5 cm