Two identical taps fill 2/5 of a tank in 20 minutes. when one of the taps goes dry in how many minutes will the remaining one tap fill the rest of the tank ?
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Answered by
4
The two taps are identical, that means they fill the same fraction of the tank in the same time.
If the two taps fill 2/5 of the tank in 20 minutes, then in 1 minute they fill:
2/5 ÷ 20 = 2/5 × 1/20 = 1/50
Both taps fill 1/50 of the tap in 1 minute
Therefore 1 tap fills : (divide by 2)
1/50 ÷ 2 = 1/50 × 1/2 = 1/100
The fraction of the tank filled by 1 tap in 1 minute = 1/100
The remaining fraction of the tank to be filled = 5/5 - 2/5 = 3/5
Calculate the time it takes the remainig tap to fill the rest of the tank:
If 1/100 of the tank = 1 minute
Then 3/5 = 1 × 3/5 ÷ 1/100
= 3/5 x 100/1 = 300/5 = 60 minutes
Therefore it will take the other tap 60 minutes to fill the remaining portion of that tank.
If the two taps fill 2/5 of the tank in 20 minutes, then in 1 minute they fill:
2/5 ÷ 20 = 2/5 × 1/20 = 1/50
Both taps fill 1/50 of the tap in 1 minute
Therefore 1 tap fills : (divide by 2)
1/50 ÷ 2 = 1/50 × 1/2 = 1/100
The fraction of the tank filled by 1 tap in 1 minute = 1/100
The remaining fraction of the tank to be filled = 5/5 - 2/5 = 3/5
Calculate the time it takes the remainig tap to fill the rest of the tank:
If 1/100 of the tank = 1 minute
Then 3/5 = 1 × 3/5 ÷ 1/100
= 3/5 x 100/1 = 300/5 = 60 minutes
Therefore it will take the other tap 60 minutes to fill the remaining portion of that tank.
Answered by
7
Answer:
2/5 of the tank is filled by 2 identical taps in 20 mins.
remaining part of the tank left is (1-2/5)=3/5
so time taken by 1tap for filling 2/5th of tank=(20/2)=10 mins (bcoz two taps are identical)
hence time taken by 1 tap to fill the entire tank=10*5/2=25 mins
so, time taken to fill the remaining 3/5th of the tank will be = 25*3/2=15 mins
Answer 15 min
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