Two identical taps fill 2/5 of a tank in 20 minutes. When one of the taps goes dry in how many minutes will theremaining one tap fill the rest of the tank ?
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The two taps are identical, that means they fill the same fraction of the tank in the same time.
If the two taps fill 2/5 of the tank in 20 minutes, then in 1 minute they fill:
2/5 ÷ 20 = 2/5 × 1/20 = 1/50
Both taps fill 1/50 of the tap in 1 minute
Therefore 1 tap fills : (divide by 2)
1/50 ÷ 2 = 1/50 × 1/2 = 1/100
The fraction of the tank filled by 1 tap in 1 minute = 1/100
The remaining fraction of the tank to be filled = 5/5 - 2/5 = 3/5
Calculate the time it takes the remainig tap to fill the rest of the tank:
If 1/100 of the tank = 1 minute
Then 3/5 = 1 × 3/5 ÷ 1/100
= 3/5 x 100/1 = 300/5 = 60 minutes
Therefore it will take the other tap 60 minutes to fill the remaining portion of that tank.
If the two taps fill 2/5 of the tank in 20 minutes, then in 1 minute they fill:
2/5 ÷ 20 = 2/5 × 1/20 = 1/50
Both taps fill 1/50 of the tap in 1 minute
Therefore 1 tap fills : (divide by 2)
1/50 ÷ 2 = 1/50 × 1/2 = 1/100
The fraction of the tank filled by 1 tap in 1 minute = 1/100
The remaining fraction of the tank to be filled = 5/5 - 2/5 = 3/5
Calculate the time it takes the remainig tap to fill the rest of the tank:
If 1/100 of the tank = 1 minute
Then 3/5 = 1 × 3/5 ÷ 1/100
= 3/5 x 100/1 = 300/5 = 60 minutes
Therefore it will take the other tap 60 minutes to fill the remaining portion of that tank.
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