Question

Two identical thin rings, each of radius a meter, are coaxially placed at a distance R meter apart. If Q₁ coulomb and Q₂ coulomb are respectively the charges uniformly spread on the two rings, the work done in moving a charge q coulomb from the centre of one ring to that of the other is(a) Zero(b) $\frac{q(Q_{1}-Q_{2})(\sqrt{2}-1)}{4\sqrt{2}\pi\epsilon_{0}a}$(c) $\frac{q\sqrt{2}(Q_{1}+Q_{2})}{4\pi\epsilon_{0}a}$(d) $\frac{q(Q_{1}+Q_{2})(\sqrt{2}+1)}{4\sqrt{2}\pi\epsilon_{0}a}$

Answer 1

HERE IS YOUR ANSWER :-

Option No. C

Thanx❤❤❤

✌✌✌Follow Me✌✌✌

Answer 2

Answer:

$\scriptsize\mathtt \pink{=\frac{1}{4 \pi \varepsilon_{0}} \frac{q_{1}}{r_{1 p }^{2}} \hat{ r }_{1 P }+\frac{1}{4 \pi \varepsilon_{0}} \frac{q_{2}}{r_{2 P }^{2}} \hat{ r }_{2 P }+\ldots .+\frac{1}{4 \pi \varepsilon_{0}} \frac{q_{n}}{r_{n P }^{2}} \hat{ r }_{n P }}$