Question

Two identical wires of steel and copper respectively are stretched by the same weight
in turn.Calculate the ratio of the extensions produced in the wires. Y for steel and
copper are 2 x 10^11 and 1.2 x 10^11 Nm^-2 respectively.
​

Answer 1

Answer:

l=

AY

FL

⟹

l

Cu

l

s

=

Y

S

Y

Cu

(F,L and Y are constant)

∴

l

Cu

l

s

=

2×10

11

1.2×10

11

=

5

3

Explanation:

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