Question

Two impedance Z1 = (10 + j15) Ω and Z2 = (20 – j25) Ω are connected in parallel, which is connected in series with Z3 = (25 + jX) Ω. Find the value and nature of X to get resonance.

Answer 1

Answer:

Solution: 42.25+j(x+5.73)

In polar form 43.64<14.50

Explanation:

in rectangular form 42.25+j(x+5.73)

In polar form 43.64<14.50

X should be -5<x<infinity

And should be an inductance.